A pyramid has a square base of length 16 cm .Given that the slant height of the pyramid is 17 cm . Find its total surface area.
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Given, OG = 15 cm GF = 1212 × side of square = 8 cm ∴ Height of triangle = OF = 152+82−−−−−−−√=225+64−−−−−−−√152+82=225+64 =289−−−√289 =17 cm ∴ Area of the lateral surface of the pyramid = 4 × Area of one triangle edge = 4 ×1212 × base × height = 4 × 1212 × 16 × 17 = 544 sq. cm.
Answer is 544 sq. cm
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