a quadartic polynomial x2-x+10 whose zeroes are -3&4
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bro the question
has the false roots which you have mentioned in the question
as the equation has imaginary roots as descriment is less than 0
bro I will give the ans
as taking your question in two parts
as find the
roots of x²-x+10
and the find the equation of the polynomial whose roots are -3 and 4
I) by using the root formula
x= [- b±√(b²-4ac)]/2a
and when we solve it
we have roots
x= (1±i√39)/2
ii) equation of the roots of the zeros -3 and 4
sum of roots = 1
product of roots = -12
so equation is
x²-(sum of roots)x + product of roots
x²-x-12
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