Question

A quadratic equation whose one root is 3 is *

1 point

x2 + 6x − 5 = 0

x2 − 5x + 6 = 0

x2 − 5x − 6 = 0

x2 − 6x − 5 = 0​

Answer 1

We can solve it by substituting the values...

1st option :

3² + 6×3 - 5

= 9+27-5

= 31 ≠0

So , it's wrong..

2nd option :

3²-5×3+6

= 9-15+6

=15-15

= 0

So ,

Option 2 is correct !!!!!

Answer 2

We can solve it by substituting the values...

1st option :

3² + 6×3 - 5

= 9+27-5

= 31 ≠0

So , it's wrong..

2nd option :

3²-5×3+6

= 9-15+6

=15-15

= 0

So ,

Option 2 is correct !!!!!