A quadratic equation x(x + k) = 5 has one of its roots equal to 1, what is the other root?
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hey !!
X ( X + K ) = 5
X² + KX = 5
P ( x ) = X² + KX - 5 = 0
P (1) = (1)² + K × 1 - 5
=> 1 + K - 5 = 0
=> K - 4 = 0
=> K = 4.
P ( x ) = X² + KX - 5 = X² + 4X - 5.
Here,
a = 1 , b = 4 and c = -5.
Sum of zeroes = -b/a
1 + other root = -4/1
other root = -4 - 1
Other root = -5
X ( X + K ) = 5
X² + KX = 5
P ( x ) = X² + KX - 5 = 0
P (1) = (1)² + K × 1 - 5
=> 1 + K - 5 = 0
=> K - 4 = 0
=> K = 4.
P ( x ) = X² + KX - 5 = X² + 4X - 5.
Here,
a = 1 , b = 4 and c = -5.
Sum of zeroes = -b/a
1 + other root = -4/1
other root = -4 - 1
Other root = -5
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