Question

a quadratic polynomial has sum of zeros 2 and product of zeroes are - 3/7.
find the polynomial ​

Answer 1

$\large \bf \clubs \:  Given :-$

For a Quadratic Polynomial :

   

• Sum of Zeros = 2

• Product of Zeros = -3/7

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$\large \bf \clubs \:   To  \: Find :-$

• The Quadratic Polynomial.

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$\large \bf \clubs \:   Main  \:  Concept : -$

☆ If sum and product of zeros of any quadratic polynomial are S and P respectively,

Then,

The quadratic polynomial is given by :-

$\large\bf  {x}^{2}  - S \: x + P$

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$\large \bf \clubs \:  Solution  :-$

Here,

• Sum = S = 2

• Product = P = -3/7

So,

Required Polynomial should be :

$\large \bf  {x}^{2}  - S \: x + P$

$\large:\longmapsto  \tt{x}^{2} - 2x+ \bigg(-\dfrac{3}{7}\bigg)$.

$\Large\purple{:\longmapsto\pmb{7 {x}^{2}  -14x -3}}$

$\Large \red{\mathfrak{  \text{W}hich \:   \: is  \:  \: the  \:  \: required} }\\ \huge \red{\mathfrak{ \text{ A}nswer.}}$

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Answer 2

$\huge \boxed{ \bf \red{7 {x}^{2} - 14x - 3}}$

Step-by-step explanation:

QUESTION :-

A quadratic polynomial has sum of zeros 2 and product of zeros are -3/7. Find the polynomial.

_________________________

SOLUTION :-

For the quadratic polynomial,

• Sum of zeros (S) = 2
• Product of zeros (P) = -3/7

To find the quadratic polynomial, we use formula -

x² - (S)x + P

$= > {x}^{2} - (2)x + ( \frac{ - 3}{7} ) \\ \\ = > {x}^{2} - 2x - \frac{3}{7}$

[multiply the polynomial by 7]

$= > 7( {x }^{2} - 2x - \frac{3}{7} ) \\ \\ = > 7 {x}^{2} - 14x - 3$

So,

the required quadratic polynomial is 7x² - 14x - 3.

Hope it helps.

#BeBrainly :-)