Question

A quadratic polynomial the sum and product of whose zeroes are 3and-10 respectively is

Answer 1

Answer:

Step-by-step explanation:

Alpha + beta = 3

alpha. beta = -10

Eq = x² - (alpha + beta) X + (alpha. Beta)

= x² - (3)x + (-10)

= x² - 3x - 10 = 0

Hope it helps uh

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Answer 2

Substituting S and P in:

x^2 - Sx + P=0

x^2- 3x+ (-10)=0

x^2-3x-10=0