Question

A quadratic polynomial whose sum and product of zeroes and 1/5 and -4 is
(a)
$4 {x}^{2} - x - 4$(b)
$4 {x}^{2} + x + 4$(c)
$5 {x}^{2} - x - 4$(d)
$5 {x}^{2} - x - 20$



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Answer 1

Step-by-step explanation:

if we know sum and product of zeros then polynomial is =k(x^2-x(sum)+product)

so = k(x^2-x(1/5)-4)

here k =5

polynomial is 5x^2-x-20

which is option d