Math, asked by maanvicky881, 8 months ago

a quadratic polynomial whose zero es are -4 and -5. is​

Answers

Answered by Anonymous
21

Answer:

a = -4 , ß = -5

Q = x²- (a + ß)x + (a × ß)

Q = x²- (-4+(-5))x + (-4×-5)

Q = x²- (-9)x + (-20)

Q = x² + 9x - 20

Thank you

Answered by nairaryaashok01
0

Answer:

The required quadratic polynomial is x²+9x+20

Step-by-step explanation:

We know that,

The structure of a quadratic equation is given by ax²+bx+c=0

Given:

α=-4 β=-5

Sum of zeros=\alpha +\beta =-4+-5=-9

Product of zeros=\alpha \beta =-4*-5=20

The quadratic polynomial equation can also be written as

k[x² – (α + β)x + αβ].    (k is a constant)

∴kx²-(-9x)+20

Assuming k to be 1, we get

x²+9x+20

Therefore, the required quadratic polynomial is x²+9x+20

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