Question

a quadratic polynomial whose zero es are -4 and -5. is​

Answer 1

Answer:

a = -4 , ß = -5

Q = x²- (a + ß)x + (a × ß)

Q = x²- (-4+(-5))x + (-4×-5)

Q = x²- (-9)x + (-20)

Q = x² + 9x - 20

Thank you

Answer 2

Answer:

The required quadratic polynomial is x²+9x+20

Step-by-step explanation:

We know that,

The structure of a quadratic equation is given by ax²+bx+c=0

Given:

α=-4 β=-5

Sum of zeros=$\alpha +\beta =-4+-5=-9$

Product of zeros=$\alpha \beta =-4*-5=20$

The quadratic polynomial equation can also be written as

k[x² – (α + β)x + αβ].    (k is a constant)

∴kx²-(-9x)+20

Assuming k to be 1, we get

x²+9x+20

Therefore, the required quadratic polynomial is x²+9x+20