a quadratic polynomial whose zero es are -4 and -5. is
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Answered by
21
Answer:
a = -4 , ß = -5
Q = x²- (a + ß)x + (a × ß)
Q = x²- (-4+(-5))x + (-4×-5)
Q = x²- (-9)x + (-20)
Q = x² + 9x - 20
Thank you
Answered by
0
Answer:
The required quadratic polynomial is x²+9x+20
Step-by-step explanation:
We know that,
The structure of a quadratic equation is given by ax²+bx+c=0
Given:
α=-4 β=-5
Sum of zeros=
Product of zeros=
The quadratic polynomial equation can also be written as
k[x² – (α + β)x + αβ]. (k is a constant)
∴kx²-(-9x)+20
Assuming k to be 1, we get
x²+9x+20
Therefore, the required quadratic polynomial is x²+9x+20
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