Question

A quadratic polynomial whose zeroes are -3 and 4
a ) x square -x +12 b) x square +x+12
C) 2x square +2x - 24 d) none of these

Answer 1

Given:-

๛α=-3

๛β=4

$\rule{200}{1}$

To Find:-

→A quadratic polynomial among them whose zeros are -3&4:-

•a) x²-x+12

•b) x²+x+12

•c) 2x+2x-24

•d) None of these

$\rule{200}{1}$

AnsWer:-

★Applying Quadratic Formula★

→k[x²-(α+β)x+αβ)]–(1)

→α+β=-3+4

→α+β=1–(2)

→αβ=(-3)×4

→αβ=-12–(3)

★Using (2)&(3) in (1)★

→k[x²-(1)x+(-12)]

→k[x²-x-12]

♦Let k=1♦

→1[x²-x-12]

→x²-x-12

๛Hence, Option d) None of these is the correct answer.

$\rule{200}{2}$

Answer 2

Hello!

Given roots are -3 and 4.

We can write the equation as:

x = -3 or x = 4

(x + 3) = 0 or (x-4) = 0

(x + 3)(x-4) = 0

x(x - 4) + 3(x - 4) = 0

x² - 4x + 3x - 12 = 0

x²- x - 12 = 0

Hence, the required equation is x² - x - 12 = 0.

Therefore, None of the given options is correct.