Question

A quadratic polynomial, whose zeroes are -3 and 4 ,find it

Answer 1

$let \: \: \alpha = - 3 \\ \beta = 4 \\ \\ sum \: \: of \: \: zeroes = \alpha + \beta \\ = - 3 + 4 = 1 \\ \\ product \: \: of \: \: zeroes = \alpha \beta \\ = - 3 \times 4 = - 12 \\ \\ quadratic \: \: polynomial \\ = {x}^{2} - ( \alpha + \beta )x + \alpha \beta \\ = {x}^{2} - 1x - 12$

Answer 2

Step-by-step explanation:

The formula to calculate quadratic equation is

x^2-(P+Q)x+PQ=0

where P and Q are zeroes of equation.

P+Q= -3+4

= 1

PQ= (-3)(4)

= -12

therefore the equation Will be

x^2-1x-12=0

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