A quadratic polynomial, whose zeroes are -3 and 4,is
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0
Answer:
x2+1x-12
Step-by-step explanation:
p(x)= x2- ( sum of zeroes )x + ( product of zeroes ).
= x2- ( -3+4)x +( -3×4)
= x2- (-1)x + (-12)
= x2+1x-12
Hope it will help you.........
Answered by
6
Solution -
The required Zeroes are -3 and 4 .
Sum of Zeroes -
=> -3 + 4
=> 1
Product Of Zeroes -
=> ( -3 )( 4 )
=> -12
Now , a quadratic polynomial can be written as -
x² - ( Sum of Zeroes ) x + ( Product Of Zeroes )
=> x² - ( 1 ) x - 12
=> x² - x - 12
Verification -
x² + x - 12
=> x² - 4x + 3x + 12
=> x ( x - 4 ) + 3 ( x - 4 )
=> ( x + 3 )( x - 4 )
Zeroes -
=> -3, 4
Hence Verified -
Additional Information -
In a Polynomial -
Sum of Zeroes = ( -b / a )
Product Of Zeroes = ( c / a )
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