how much work is to be done in bringing the charges+1C,+2C,+4C on vertix of equilateral triangle with 1m length of side
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Answer:
Work done on the system is change in their potential energies in two configuration.
q
1
=1C
q
2
=2C
q
3
=3C
So initial potential energy of arrangement
r=1m
U=h(
r
q
1
q
2
+
r
q
2
q
3
+
r
q
3
q
1
)[h is constant 9×10
9
]
=h(
1
2+6+3
)
U
initial
=11h→(1)
Initial potential energy of arrangement r=0.5m
U
final
=h(
r
q
1
q
2
+
r
q
2
q
3
+
r
q
3
q
1
)
=h(
0.5
2+6+3
)
=22h→(2)
Work done=U
final
−U
initial
=22h−11h
=11×9×10
9
=99×10
9
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