A quadratic polynomial, whose zeroes are -3 and 4, is
(a) x²- x + 12
(b) x² + x + 12
(c) x22−x2−6
(d) 2x² + 2x – 24
answer in detailed method
Answers
Answered by
1
here they asked that quadratic polynomials whose zeroes are -3 and 4
the values -3 and 4 just put that to the place give the value to X as -3 and 4 and simplify you will get your answer ..
please mark me as brainlist
Answered by
8
Answer:
x²-x-12
Step-by-step explanation:
Given that,
α= (-3) and β= 4
α+β= -3+4=1
αβ= -3×4= (-12)
Now, we know that,
k[x²-(α+β)x+(αβ)] gives the polynomial
Putting the values, we get
=> k[x²-(1)x +(-12)]
=> k[ x² -x -12]
=> x²-x-12
Hence the required polynomial is x²-x-12
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