Question

 A quadratic polynomial, whose zeroes are -3 and 4, is
(a) x²- x + 12
(b) x² + x + 12
(c) x22−x2−6
(d) 2x² + 2x – 24
answer in detailed method


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Answer 1

here they asked that quadratic polynomials whose zeroes are -3 and 4

the values -3 and 4 just put that to the place give the value to X as -3 and 4 and simplify you will get your answer ..

please mark me as brainlist

Answer 2

Answer:

x²-x-12

Step-by-step explanation:

Given that,

α= (-3) and β= 4

α+β= -3+4=1

αβ= -3×4= (-12)

Now, we know that,

k[x²-(α+β)x+(αβ)] gives the polynomial

Putting the values, we get

=> k[x²-(1)x +(-12)]

=> k[ x² -x -12]

=> x²-x-12

Hence the required polynomial is x²-x-12