Question

a quadratic polynomial , whose
zeroes are -3 and 4. so find out quadratic polynomial​

Answer 1

Step-by-step explanation:

$\alpha = - 3 \\ \beta = 4 \\ \alpha + \beta = - 3 + 4 \\ = 1 \\ \alpha \beta = - 3 \times 4 \\ = - 12 \\ {x}^{2} - ( \alpha + \beta )x \: + \alpha \beta = 0 \\ {x}^{2} + x - 12 = 0$

Answer 2

Answer:

above is your answer ✋

mark brainlist