Question

A quadratic polynomial whose zeroes are -3 and 4is
(a) x-x+12 (b) x+x+12 (c) 2x + 2x–24.
(d) none of theabove.​

Answer 1

Answer:

We need to find the values of x and y.

Step-by-step explanation:

Since the quadrilateral ABCD is a rectangle, the opposite sides must be same in length.

Thus we can write the following set of equations

x + y = 12            ... (1)

x – y = 8              ... (2)

Adding Equations (1) and (2), we get

Substituting the obtained value of x in Equation (1), we get

Therefore, given the rectangle ABCD, x = 10 and y = 2.

Answer 2

Answer:

d) none of the above.

first sum of zeros

we take alpha as -3 and beta as 4 .

then alpha+ beta = -b÷a

it gives : -3+4 = -b÷a

1 = -b÷a

b÷a = 1

product of zeros ...

alpha×beta = c

(-3) (4)= c÷a

-12 = c÷a

c÷a = 12

a=1 ,b=-1, c=-12

quadratic eq is

ax*2+ bx+c