Question

a quadratic polynomial whose zeroes are-3and 4 is​

Answer 1

Given ,

Product of zeroes = (-3) × 4 = -12

Sum of zeroes = (-3) + 4 = 1

We know that , the quadratic equation is given by

$\large{ \green{ \sf \star \: \: \fbox{ \fbox{ \red{ {x}^{2} - (Sum \: of \: zeroes )x + (Product \: of \: zeroes ) = 0}}} }}$

Substitute the values , we obtain

$\sf \hookrightarrow {x}^{2} - x + ( - 12) = 0 \\ \\ \sf \hookrightarrow {x}^{2} - x - 12 = 0$

Hence , the required eq is x² - x - 12 = 0