Question

A quadratic polynomial,whose zeroes are-3and4 is

Answer 1

Heya !!!


Let Alpha = -3 and beta = 4

Therefore,



Sum of zeroes = Alpha + Beta = -3 + 4 = 1


And,

Product of zeroes = Alpha × Beta = -3 × 4 = -12


Therefore,



Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes


=> X²-(1)X + (-12)

=> X²-X-12




HOPE IT WILL HELP YOU...... :-)

Answer 2

Heya here ,

Solution -----------------

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$let \: \: \alpha = - 3 \: \: and \: \beta = 4$
$sum \: \: of \: zeroes \: ( \alpha + \beta ) = - 3 + 4 = 1 \\ \\ product \: \: of \: \: zeroes \: ( \alpha \beta ) = - 3 \times 4 = - 12 \\ \\ required \: \: polynomial \: \\ = {x}^{2} - (\alpha + \beta )x \: \: + \: \alpha \beta \\ \\ = > {x}^{2} -x - 12$

hence, x^2 - x - 12 is the Polynomial
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