Question

A quadratic polynomial x2 -7 have zero’s,​

Answer 1

Answer:

${x}^{2} - 7 = 0 \\ so \\ x = + \sqrt{7} \: and \: x = - \sqrt{7}$

Answer 2

The quadratic polynomial x² - 7 have zeroes as - √7 & √7

Given :

The polynomial x² - 7

To find :

The zeroes of the polynomial

Solution :

Step 1 of 2 :

Write down the given polynomial

Let p(x) be the given polynomial

Then p(x) = x² - 7

Step 2 of 2 :

Find zeroes of the polynomial

For Zeroes of the polynomial we have

$\displaystyle \sf{ p(x) = 0}$

$\displaystyle \sf{ \implies {x}^{2} - 7 = 0}$

$\displaystyle \sf{ \implies {x}^{2} - {( \sqrt{7} )}^{2} = 0}$

$\displaystyle \sf{ \implies (x + \sqrt{7})(x - \sqrt{7} )= 0}$

x + √7 = 0 gives x = - √7

x - √7 = 0 gives x = √7

Hence the quadratic polynomial x² - 7 have zeroes - √7 & √7

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