a quadrilateral ABCD , ∠A+∠B=90◦ , AB=8, CD=6 and AC=5√3 then BD=
Answers
Answered by
6
Answer:
ANSWER
2S=5+4+3 ⇒ S=6
Area of ΔABC
=
s(s−a)(s−b)(s−c)
=
15(15−9)(15−8)(15−13)
=
6(1)(2)(3)
=
36
=6
⇒For area of ΔADC,
⇒2S=5+4+5
⇒ S=7cm
⇒Area of ΔADC
=
7(7−5)(7−5)(7−4)
=
7×2×2×3
=2
21
=9.16m
2
⇒Area of quad ABCD= Area of (△ABC+△ADC)
=6+9.16
=15.16 cm
2
≈15.2 cm
2
Attachments:
Similar questions