A quadrilateral ABCD has four angles x⁰, 2x⁰, 5x⁰ / 2 and 7x⁰ / 2 respectively. What is the difference between the value of biggest and the smallest angle.(A) 40⁰ (B) 100⁰(C) 80⁰ (D) 20⁰
Answers
Answered by
15
here,
x°+2x°+5x°/2+7x°/2= 360°
=>(2x°+4x°+5x°+7x°) ÷ 2=360°
=>18x°=360°×2
=>18x°=720°
=>x=(720÷18)°
=>x=40°
So, x°=40°,
2x°=2×40=80°,
5x°/2=(5×40)÷2=100°,
7x°/2=(7×40)÷2=140°
we can see that the smallest value of angle is 40° and the biggest value of angle is 140°.
So,the difference between the value of biggest and the smallest angle is =(140 - 40)°=100°
x°+2x°+5x°/2+7x°/2= 360°
=>(2x°+4x°+5x°+7x°) ÷ 2=360°
=>18x°=360°×2
=>18x°=720°
=>x=(720÷18)°
=>x=40°
So, x°=40°,
2x°=2×40=80°,
5x°/2=(5×40)÷2=100°,
7x°/2=(7×40)÷2=140°
we can see that the smallest value of angle is 40° and the biggest value of angle is 140°.
So,the difference between the value of biggest and the smallest angle is =(140 - 40)°=100°
Answered by
2
Answer:
(B) 100
Step-by-step explanation:
Similar questions