Math, asked by mahendr49, 4 months ago

A quadrilateral ABCD is drawn to circumscribe a circle. Prove that AB + CD = AD + BC.​

Answers

Answered by jeetmit4
1

Answer:

let quad ABCD circumscribe a circle or all sides are tangent to it.

let AB touch the circle at P

BC touch the circle at Q

CD touch the circle at R

DA touch the circle at S

AP=AS

RD=DS

RC=QC

PB=BQ        OR, AP+RD+RC+PB=AS+DS+QC+BQ     OR, AB+CD=AD+BC

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Step-by-step explanation:

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