A quadrilateral of diagolnal is 24 cm and 10 cm . What is the perimeter of quadrilateral
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Answer:
As the diagonal bisected each other then
10÷2=5
24÷2=12
as they bisected at right angle so we use Pythagoras theorem
(each side of the quadrilateral)^2=
(5)^2+(12)^2
=25+144
=169
by rooting
answer will be 13.
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If the diagonals measure 24 cm and 10 cm, then by the Pythagorean theorem each side has a length of 13 cm. Therefore, the perimeter of the rhombus is equal to 4 x 13 or 52 cm.
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