A quantity of 10g of a hydrocarbon exactly requires 40g of oxygen for complete combustion the product formed are co2 and water when co2 gas formed is absorbed completely in lime water the mass of solution increase by 27.5g what is the mass of water formed in combustion
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The reaction is as follows:
2 ZnS(s) + 3 O2(g) → 2 ZnO + 2 SO2
we see that 2 moles of ZnS gives 2 moles of ZnO and 2 moles of SO2. So,
Number of moles of ZnS = Given massmolar mass=4.86697.474=0.0499 moles
Mass of ZnO = 81.408 ×0.0499 = 4.045 g
Mass of SO2 = 64.06 × 0.0499 = 3.19 g.
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