Question

A quantity of 1kg of 1molar glucose solution is diluted to 5kg the molality of diluted solution should be ​

Answer 1

Let mass of  C6H12O6  be  x  (gm) in 1 molal solution.

Then  x18010001000−x=1  (Molar mass of  C6H12O6  is  180gm )

Hence  x=1800001180≈152.54  

Now diluted solution weighs  5kg . Upon dilution, number of moles of glucose (or mass of glucose) remains unchanged. Hence the mass of solvent becomes  5000−152.54gm=4847.46gm  

Hence molality of resulting  C6H12O6 solution will be :

m=152.5418010004847.46molkg−1  

m = 0.17 molal

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