Question

A quantity of gas has a volume of 0.20 m3 and an absolute temperature of 333 K. When the temperature of the gas is raised to 533 K, what is the new volume of the gas? (Assume there's no change in pressure). A. 0.2333 m3 B. 0.0006 m3 C. 0.2146 m3 D. 0.3201 m3

Answer 1

When there is no change in pressure, we can use the formula

V1/T1 = V2/T2

V1 = 0.2m³

V2 = ?

T1 = 333K

T2 = 533K

0.2/333 = V2/533

V2 = (0.2/333) x 533

V2 = 0.32 m³

Answer 2

According to Charles’s law of ideal gas the volume of ideal gas is directly proportional to the temperature of the ideal gas.

It can be shown as:

$\bold{\frac{V 1}{T 1}=\frac{V 2}{T 2}}$

Given:

$\mathrm{V} 1=0.20 \mathrm{m}^{3}$

T1 = 333 K

V2 = need to calculate  

T1 = 533 K

Plug the given values:

$\frac{0.20}{333 K}=\frac{V 2}{533 K}$

$V 2=\frac{0.20 \times 533}{333}=0.3201\ \mathrm{m}^{3}$

Hence the new volume of ideal gas must be $\bold{0.3201\ \mathrm{m}^{3}.}$