Question

A quantity of heat Q is supplied to a monoatomic ideal gas which expands at constant pressure. The fraction of heat that goes into the work done by the gas is...

Answer 1

Q=mcp dt

cp for monoatomic gas =5/2*R

where R=1.98calmole^-1 K-1

hope it helps u dear

Answer 2

$\sf\huge{Answer}$

$\sf\bold{Question}$==>

A quantity of heat Q is supplied to a monoatomic ideal gas which expands at constant pressure. Calculate the fraction of heat that goes into the work done by the gas.

Solution=>

from the First law of thermodynamics..

we have..

∆Q =∆W + ∆U

∆W = ∆Q - ∆U==(1)

Dividing the equation by ∆Q...

$\frac{W}{Q}$ = $\frac{Q}{Q}-\frac{U}{Q}$

$\frac{W}{Q}$ =1 - $\frac{U}{Q}$

we have,

∆Q = C(p)N∆T

∆U = C(v)N∆T

$\frac{W}{Q}$ = 1-$\frac{C(v)NT}{C(p)NT}$

$\frac{W}{Q}$ = 1-$\frac{1}{Y}$

where, $\frac{C(p)}{C(v)}$ = Y...

and for monoatomic gas, we have,,

Y = $\frac{5}{3}$

substituting..

$\frac{W}{Q}$ = 1-$\frac{3}{5}$

$\frac{W}{Q}$ = $\frac{5-3}{5}$

$\frac{W}{Q}$ = $\frac{2}{5}$

$\frac{W}{Q}$ = $\frac{2}{5}$

(or)

$\frac{W}{Q}$= $\frac{2}{5}$= 0.4...

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