Question

A quantity of hydrogen gas occupies a volume 30 ml at a certain temperature and pressure. What volume would half the mass of hydrogen occupy at triple the absolute temperature is the pressure were one ninth that of the original gas.

Answer 1

If half of the mass of hydrogen occupy at triple the absolute temperature if the pressure were one-ninth the original gas,

So \frac{p}{9}\times 30= \frac{n_1}{2}\times R\times 3T

9

p

×30=

2

n

1

×R×3T

V= \frac{9\times 30\times 3}{2}= 405mLV=

2

9×30×3

=405mL

Hence option C is correct