Question

A question for all cricket lovers, maths genious in the group !!
How many runs a single player can score in One day match (50 overs/ 300 balls)

No 'no balls', no wides, no extras, no over throws...So how much runs he can score max???

this quetion came in IIT and 99% people answered it wrong..

Choices :
A) 1800.
B) 1650.
C) 1653.
D) 1550.
E) 1555
F) 1506

Answer 1

C) 1653.

Explanation:

Lets says there are two batsmen X & Y. Let us assume Batsman X is on strike first-up, and the batsmen would hit "5 consecutive sixes" only to take 3 runs off the last ball of the over, and hence the 1st over would yield "33 runs".

By taking 3 runs (either 1 or 3 since, here we speak about max runs, we will take 3 runs) off the last ball of the 1st over, Batsman X  would be able to  "retain strike" for the "next over". In the 2nd over, Batsman X follows the "same scoring pattern" so as to accumulate "another 33 runs".

Therefore, for 49 overs,

First 5 balls = 6*5 =30

Last ball = 1*3 = 3.

So, 33 runs for 49 overs.

will be, 49*33 = 1617 _________________ (a)

And for the last over, he would hit all balls for a six, since there is no next over, hence

For all six balls, 6*6 = 36 ______________ (b)

Thus, from a+b we get,

1617 + 36 = 1653

Hence, with the help of "251 sixes and 49 threes" in the innings, the answer  is 1653 runs.

To know more

Some quiz related to sports with answers pls - Brainly.in

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Answer 2

Option C - 1653 runs

Given data:

A player should score in a One-day match (50 overs/ 300 balls)  with no 'no balls', no wides, no extras, no overthrows.

To find:

The maximum runs he could score as per the information given.

Solution:

To get the maximum runs under the given condition,

For the first 49 overs, the first five balls of each over should get hit as a six.

The last ball of each over should be a 3 run, in order to get the strike for the next over as in maximum (as there are no overthrows.)

So, for each over in the first 49 overs, we get

For first 5 balls of the over :  5 x 6 = 30

For the last ball of the over: 1 x 3 = 3

Total per over = 30+3 = 33 runs

So, for the first 59 overs, he scores 33 x 49 = 1617 runs

In the last over, as the strike stays with him throughout, he can hit 6 sixes out of the park and finish the match.

So, in the last over i.e., 50th over, he scores 6 x 6 = 36 runs

Total runs he score in the 50 overs = 1617 + 36 = 1653 runs.

Therefore, the maximum number of runs the player can score in a one-day match of 50 overs is 1653 runs (with no 'no balls', no wides, no overthrows, no extras).

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