What is the probability that the sum of the digits of a 10-digit number is divisible by 10?
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Step-by-step explanation:
Given What is the probability that the sum of the digits of a 10-digit number is divisible by 10?
- Probability = Favourable outcome / Total number of outcomes
- Now all possible outcomes will be 9000000000 (because there are 1 x 10 ^9 to 9 x 10^9)
- So favourable outcome will be 9000000000 / 10 (because the number has to be divisible by 10 and the last digit should be 0)
- So probability = 9 x 10^8 / 9 x 10^9
- = 1 / 10
- = 0.1
Reference link will be
https://brainly.in/question/6603102
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