Question

a race car accelerate uniformly from 18.5 m/s to 46.1 m/s in 2.47 sec find distance​

Answer 1

Answer:

4.83 m

Explanation:

18.5 sub 2.47sec and 46.1sub 2.47sec

Answer 2

Answer:

Given:-

Initial velocity (u) = 18.5m/s

Final velocity (v) = 46.1m/s

Time = 2.47sec

To find:-

Distance

By applying, v - u = at

46.1 - 18.5 = a×2.47

27.6 = 2.47a

a = 27.6/2.47

= 11.17408m/s^2.

By applying, v^2 - u^2 = 2as

2125.21 - 342.25 = 2×11.17408×s

1782.96 = 22.34816s

S = 1782.96/22.34816

= 79.78106m.