A race car accelerates on a straight road from rest to a speed of 180km/h in 25 s. Assume uniform acceleration of car throughout, find the distance covered in this time.
Answers
Answered by
293
u= 0 , v= 180km/hr = 180×5/18=50m/s, t= 25s
v=u+at
50= 0+a×25
50=25a
a= 50/25
a= 2m/s^2
s=ut+1/2at^2
s= 0×25+1/2×2×(25)^2
s= 1/2×2×625
s= 625m
s= 0.625 km
v=u+at
50= 0+a×25
50=25a
a= 50/25
a= 2m/s^2
s=ut+1/2at^2
s= 0×25+1/2×2×(25)^2
s= 1/2×2×625
s= 625m
s= 0.625 km
Answered by
44
Answer:
The distance covered is 625 meter.
Explanation:
As per the theory of Kinematics,
Where initial velocity = 0 km/hour, as car starts from rest.
Final velocity, = 180 Km/hour = 180 x 1000/ 3600 = 50 m/s
t = 25 seconds
So acceleration,
Now let’s find the distance covered by the car.
Distance, d = = 625 meter
Similar questions