Physics, asked by SKhan630, 1 year ago

A race car accelerates on a straight road from rest to a speed of 180km/h in 25 s. Assume uniform acceleration of car throughout, find the distance covered in this time.

Answers

Answered by nikitasingh79
293
u= 0 , v= 180km/hr = 180×5/18=50m/s, t= 25s
v=u+at
50= 0+a×25
50=25a
a= 50/25
a= 2m/s^2

s=ut+1/2at^2
s= 0×25+1/2×2×(25)^2
s= 1/2×2×625
s= 625m
s= 0.625 km
Answered by Haezel
44

Answer:

The distance covered is 625 meter.

Explanation:

As per the theory of Kinematics,  

\mathrm{V}_{\mathrm{f}}=\mathrm{V}_{\mathrm{i}}+\mathrm{at} \quad \rightarrow(1)

Where initial velocity V_{i} = 0 km/hour, as car starts from rest.

Final velocity, \mathrm{V}_{\mathrm{f}}  = 180 Km/hour  = 180 x 1000/ 3600 = 50 m/s

t = 25 seconds

So acceleration, \mathrm{a}=\left(\mathrm{V}_{\mathrm{f}}-\mathrm{V}_{\mathrm{i}}\right) / \mathrm{t} = (50 - 0)/25 = 2 \mathrm{m} / \mathrm{s}^{2}

Now let’s find the distance covered by the car.

Distance, d = V_{i} t+\frac{1}{2} a t^{2}=(0 \times 25)+\frac{1}{2}(2) \times(252) = 625 meter

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