Question

A race car accelerates uniformly from 18.5 m/s to 46 m/s in 3.5 s. Determine the acceleration of the car and the distance travelled.

Answer 1

Explanation:

Here, initial velocity is u=18.5m/s and final velocity is v=46.1m/s

Time taken t=2.47s

If a be the acceleration of the car.

Using v=u+at,

46.1=18.5+a(2.47)

⟹ a=11.17m/s

2

If d be the distance traveled by car.

Using formula v

2

−u

2

=2ad,

(46.1)

2

−(18.5)

2

=2(11.17)d

⟹ d=79.8m

Answer 2

Answer:

the accelaration is 11.17 m/s^2

Explanation:

u=18.5 m/s

v=46.1 m/s

t=2.47 secs                                                                                                                  

a=(v-u)/t

= (46.1-18.5)/ 2.47

= 27.6/2.47= 11.17m/s^2

So, the accelaration is 11.17 m/s^2