Physics, asked by presbbbl, 7 months ago

A race car traveling on a straight part of a track has an initial velocity of 10.0 m/s. If the car then accelerates at 2.00 m/s2, how far will the car travel in 3.0 seconds?

Answers

Answered by switzrev99
1

Answer:

For example, if the velocity of a particle moving in a straight line changes uniformly ... from 2 m/s to 5 m/s over one second, then its constant acceleration is 3 m/s2. ... If a particle has an initial velocity of 6 m/s and a constant acceleration of −2 m/s2, then: ... (In exercise 6, we will find out how far the car travels during this time.) ...

Explanation:

Answered by sethrollins13
49

Given :

  • Initial Velocity ( u ) = 10 m/s
  • Acceleration = 2 m/s²
  • Time Taken = 3 seconds

To Find :

  • Distance Traveled in 3 seconds.

Solution :

For Distance :

Using 2nd Equation :

\longmapsto\tt\boxed{s=ut+\dfrac{1}{2}{at}^{2}}

Putting Values :

\longmapsto\tt{s=10(3)+\dfrac{1}{{\cancel{2}}}\times{{\cancel{2}}}\times{{(3)}^{2}}}

\longmapsto\tt{s=30+9}

\longmapsto\tt\bf{s=39m}

So , The Distance Travelled by the Car is 39m..

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Three Equations Of Motion :

  • v = u + at
  • s = ut + 1/2 at²
  • v² - u² = 2as

Here :

  • v = Final Velocity
  • u = Initial Velocity
  • t = Time Taken
  • a = Acceleration
  • s = Distance Travelled

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