Question

A race car traveling on a straight part of a track has an initial velocity of 10.0 m/s. If the car then accelerates at 2.00 m/s2, how far will the car travel in 3.0 seconds?

Answer 1

Answer:

given that:

u (initial velocity) =10.0 m/s2

a (acceleration) = 2 .00 m/s2

t (time) = 3 .0 sec

by applying equation:

$s = ut + \frac{1}{2} at {}^{2} \\ s = 10 \times 3 + \frac{1}{2} \times 2 \times 3 \\ s = 30 + 3 \\ s = 33m$

Answer 2

Given:-

• Initial velocity (u) = 10m/s

• Acceleration (a) = 2m/s²

• Time taken (t) = 3s

To Find:-

• Distance (s) covered by the car.

Solution:-

By using 3rd equation of motion

→ s = ut +1/2at²

Substitute the value we get

→ s = 10×3 +1/2×2×3²

→ s = 30 + 3×3

→ s = 30+9

→ s = 39m

∴The distance covered by the car is 39 metre.