Question

A race car traveling on a straight part of a track has an initial velocity of 10.0 m/s. If the car then accelerates at 2.00 m/s2, how far will the car travel in 3.0 seconds?​

Answer 1

Given:

• Initial velocity (u) = 10m/s
• Acceleration (a) = 2m/s²
• Time taken (t) = 3s

Need To Find:

• Distance travelled by a race car = ?

Solution:

By using second equation of motion,

⋆ s = ut + ½ at²

Putting the values,

s = 10 × 3 + ½ × 2 × 3²

s = 10 × 3 + ½ × 2 × 9

s = 30 + ½ × 2 × 9

s = 30 + 9

s = 39

Therefore,

Distance travelled by a race car is 39 m.

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Answer 2

Answer:

Given,

initial velocity (u)=10 m/s

$acceleration(a) = 2m \: per \: s^{2}$

Time (t)=3 sec

Using,

$s = ut + 1 \div 2at^{2}$

$s = 10 \times 3 + 1 \div 2 \times 2 |3^{2} |$

$s = 30 + 9$

$s = 39m$

Therefore,

distance (s)=39m