Math, asked by mrne, 3 months ago

explain it with explanation​

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Answered by BrainlyEmpire
5

{\mathfrak{\underline{\pink{\:\:\: Given:-\:\:\:}}}} \\ \\

\:\:\:\:\bullet\:\:\:\sf{Mass \: of \: object(m) = 5 \: kg  }

\:\:\:\:\bullet\:\:\:\sf{Force(F) = 20 \: N}

\:\:\:\:\bullet\:\:\:\sf{Displacement(s) = 25 \: cm}

\\

{\mathfrak{\underline{\red{\:\:\:To \:Find:-\:\:\:}}}} \\ \\

\:\:\:\:\bullet\:\:\:\sf{Work \: done \: by \: gravity \:( W.D_{g}) }

\:\:\:\:\bullet\:\:\:\sf{Work \: done \: by \: force\:( W.D_{F})}

\\

{\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}} \\ \\

☯ According to the given data:—

 \\ \:\:\:\:\bullet\:\:\:\sf{s =  \dfrac{25}{100}  = 0.25\:m} \\

\:\:\:\:\bullet\:\:\:\sf{cos \: \theta_{1} = 90 \degree} \\

\:\:\:\:\bullet\:\:\:\sf{cos \: \theta_{2} = 0 \degree}

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☯ Finding the work done by gravity

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\dashrightarrow\:\: \sf{  W.D_{g} = mg \: s \: cos \:  \theta_{1}}

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\dashrightarrow\:\: \sf{W.D_{g} =5 \times 10 \times  0.25\times cos \: 90 \degree   }

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\dashrightarrow\:\: \sf{  W.D_{g} =12.5 \times 0 }

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\dashrightarrow\:\: {\boxed{\sf{W.D_{g} =0 \: joule }}}

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☯ Finding the work done by force:——

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\dashrightarrow\:\: \sf{ W.D_{F} = F\: s \: cos \:   \theta_{2}}

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\dashrightarrow\:\: \sf{W.D_{F} =20 \times 0.25 \times cos \: 0 \degree }

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\dashrightarrow\:\:{\boxed{\sf{W.D_{F} = 5 \: joule  }}}

\\

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