Question

a race is scooter is seen accelerating uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds .determine the acceleration of the scooter and the distance travelled

Answer 1

acceleration= (46.1-18.5)/2.47
= 11.17m/s

Answer 2

Explanation :

Initial velocity of scooter, $u=18.5\ m/s$

Final velocity, $v=46.1\ m/s$

Time taken, $t=2.47\ s$

$a=\dfrac{v-u}{t}$

$a=\dfrac{46.1\ m/s-18.5\ m/s}{2.47\ s}$

$a=11.17\ m/s^2$

Using third equation of motion :

$v^2-u^2=2as$

Where,

s is the distance travelled.

$(46.1\ m/s)^2-(18.5\ m/s)^2=2\times 11.17\ m/s^2\times s$

$s=79.81\ m$

Distance covered by the scooter is 79.81 m.

Hence, this is the required solution.