A race track in the form of a ring whose inner and outer circumference are 44 and 66 cm find the width
Answers
Answered by
7
Also u can find it directly
66-44=2 pi (R-r)
[R-r=Width of track]
22=2 x 22/7 (Width of track)
(22x7)/(22x2)=3.5cm
Width of track =3.5cm
This is ur ans hope it will help you in case of any doubt comment below
66-44=2 pi (R-r)
[R-r=Width of track]
22=2 x 22/7 (Width of track)
(22x7)/(22x2)=3.5cm
Width of track =3.5cm
This is ur ans hope it will help you in case of any doubt comment below
Attachments:
Similar questions
Art,
8 months ago
Social Sciences,
1 year ago
Science,
1 year ago
Math,
1 year ago
Chemistry,
1 year ago