A race track in the form of a ring whose inner and outer circumference are 44 and 66 cm find the width
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66-44=2 pi (R-r)
[R-r=Width of track]
22=2 x 22/7 (Width of track)
(22x7)/(22x2)=3.5cm
Width of track =3.5cm
This is ur ans hope it will help you in case of any doubt comment below
66-44=2 pi (R-r)
[R-r=Width of track]
22=2 x 22/7 (Width of track)
(22x7)/(22x2)=3.5cm
Width of track =3.5cm
This is ur ans hope it will help you in case of any doubt comment below
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