Question

A race track is in the form of a ring whose inner circumference is 528m and the other circumference is 616m. Find the width of the track?

Answer 1

Heya,

Here's ur answer:-

Circumference of big circle = 616 cm
=> 2πr = 616

=> πr = 308

=> r = 308 × 7/22 = 14 × 7 = 98

Circumference of small circle = 528

=> 2πr = 528

=> πr = 264

=> r = 264 × 7/22 = 12 × 7 = 84

So, width of the track =

Radius of big circle - radius of small circle

= 98 - 84 = 14 m

So , the width of track is 14 m


If it helped plz mark BRAINLIEST

Regards
Supersonu
Ace
Brainly star

Answer 2

Brainly.in

What is your question?

shambhavim15

Secondary School Math 13+7 pts

A race track is in the form of a ring whose inner circumference is 528m and the other circumference is 616m. Find the width of the track?

Report by Nonu6149 24.11.2017

Answers

shambhavim15

Shambhavim15Ambitious

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supersonu

SupersonuMaths AryaBhatta

Heya,

Here's ur answer:-

Circumference of big circle = 616 cm

=> 2πr = 616

=> πr = 308

=> r = 308 × 7/22 = 14 × 7 = 98

Circumference of small circle = 528

=> 2πr = 528

=> πr = 264

=> r = 264 × 7/22 = 12 × 7 = 84

So, width of the track =

Radius of big circle - radius of small circle

= 98 - 84 = 14 m

So , the width of track is 14 m

If it helped plz mark BRAINLIEST