Question

a racetrack is in the form of a ring whose inner circumference is 88m and outer circumference is 110m. Then, the width of the track is ?

Answer 1

Answer: 3.5

Step-by-step explanation:

Let radius of smaller track be x

Then,

Circumference = 2*pi*x= 88

X = 88/2*pi

Let radius of larger track be y

Then,

Circumference = 2*pi*y= 110

Y= 110/2*pi

Now, the width of the track must be y-x(I have given in in a diagram as to why)

Y-x = 11/pi = 11/3.14 = 3.5

Answer 2

Answer:

Step-by-step explanation:

circumference=2*pi*x=88

x=88/2*pi

let radius of larger track be-y

circumference = 2*pi*y=110

y=110/2*pi

y-x=11/pi=11/3.14

=3.5