Question

a racetrack is in the form of a ring whose inner circumference is 220 m and outer circumfence is 308. find width

Answer 1

Answer:

14m

Step-by-step explanation:

Let r1 be the inside radius and r2 be the outside radius.

$2\pi r1=220m\\r1=\frac{220}{2\pi } \\\\r1=\frac{220}{\frac{44}{7} } \\\\r1=35m\\\\2\pi r2=308m\\r2=\frac{308}{2\pi } \\\\r2=\frac{308}{\frac{44}{7} } \\\\r2=49m\\Width=r2-r1\\=49m-35m\\=14m$