Question

A racetrack is in the form of a ring whose inner circumference is 352m. And the outer circumfrence is 396m find the width og the track

Answer 1

let r1 is inner radius

and r2 is outer radius

given 2πr1= 352m

2πr2= 39

width =r2-r1

and r1= 352/2π

and r2= 396/2π

r2-r1= 396-352/2π= 44/2π

= 7m

Answer 2

tAnswer:

Step-by-step explanation:

Let the inner radius be r1 and outer radius be r2

Circumference =2x22/7xr1

r1=(352*7)/2*22

r1=56

Circumference =2*22/7*r2

r2=(396*7)/2*22

r2=63

So width of track= r2-r1

. = 63-56

. = 7m