Physics, asked by vaishu636, 6 months ago

A racing car accerates uniformly from 25m/s to 45 m/s in 4 seconds. Determine acceration of the car and the distance travelled.​

Answers

Answered by Archisman10
0

Explanation:

Acceleration = v - u/t

Acceleration = v - u/t = 45 - 25/4

Acceleration = v - u/t = 45 - 25/4 = 20/4

Acceleration = v - u/t = 45 - 25/4 = 20/4 = 5 m/s

Acceleration = v - u/t = 45 - 25/4 = 20/4 = 5 m/sHOPE IT HELPS

Acceleration = v - u/t = 45 - 25/4 = 20/4 = 5 m/sHOPE IT HELPS IF SO, PLEASE MARK ME AS BRAINLIEST

Answered by gursharndeepkaur63
0

Answer:

Acceleration (a)=4m/S²

time (t)=10second

Initial speed=u=0Distance covered =?

We know that ,S=ut+1/2at²

=S=0×10+1/2×4×(10)²m

=S=2×100m

=S=200m

Thus,racing car will cover distance of 200m after start in 10s with given acceleration

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