Question

v=x^2y, x+y=30, find for which v is maximum or minimum​

Answer 1

Answer:

hiii

Explanation:

Let the angles be 4x,6x and 5x

4x+6x+5x=180

∘

15x=180

∘

⇒x=12

∘

So the angles are

4×12

∘

=48

∘

5×12

∘

=60

∘

6×12

∘

=72

∘

All the angles are less then 90

So triangle is an acute angled triangle.

Answer By

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Answer 2

Answer:

v is maximum when x=20 y=10

vis minimum when x=0 y is 20

answer by medical student so answer might be wrong

Explanation: