Question

A racing car has a uniform acceleration of 4 m 5 what distance will after start​

Answer 1

Here initial velocity=u

final velocity=v

acceleration=a

time=t

u=0

a=4

t=10

use the first equation of motion i.e -v=u+at

v=0+40

v=40m/s

now use third equation of motion i.e-2as=v^2-u^2

2*4*s=1600

Answer 2

$\mathfrak{\underline{Answer:-}}$

The distance covered by racing car = 200m

${\purple{\underline{\underline{\bf{\pink{Solution:-}}}}}}$

$\mathfrak{\underline{Given:-}}$

⟶ Given initial velocity is 0

⟶ Given acceleration is 4m/s²

⟶ Given time taken is 10 seconds

$\mathfrak{\underline{Need\:To\: Find:-}}$

The distance covered by racing car = ?

${\purple{\underline{\underline{\bf{\pink{Explanation:-}}}}}}$

By the second equation of motion,

$\:\:\:\:\dag\bf{\underline \green{Formula\:used\:here:-}}$

$\bigstar{\underline{\boxed{\sf\purple{s = ut + \dfrac{1}{2} at^2}}}}$

$\:\:\:\:\dag\bf{\underline \blue{Putting\:the\:values:-}}$

$\longrightarrow \sf {s = 0 \times 10 + \dfrac{1}{2} × 4 × 10 × 10}$

$\longrightarrow \sf {s = 0 + 2 \times 100}$

$\longrightarrow\large\boxed{\sf{\purple{s\:=\:200\:m}}}$

$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

The distance covered by racing car is 200m.