Question

A racing car has a uniform acceleration of 4 m s^-2. What distance will it cover in 10 s after start?​

Answer 1

Given :-

Initial velocity = 0 m/s⁻¹

Acceleration = 4 m/s⁻¹

Time period = 10 sec

To Find :-

Distance covered in 10 sec after start.

Analysis :-

Substitute the given values in the second equation of motion.

The number you get after solving it is your distance.

Solution :-

We know that,

• u = Initial velocity
• t = Time
• v = Final velocity
• a = Acceleration

Using the second equation of motion,

$\underline{\boxed{\sf Seond \ equation= s=ut+\dfrac{1}{2} at^2}}$

Given that,

Initial velocity (u) = 0 m/s⁻¹

Acceleration (a) = 4 m/s⁻¹

Time taken (t) = 10 sec

Substituting their values,

s = 0 × 1/2 (4)(4)

s = 200 m

Therefore, the car will cover a distance of 200 meters after 10 seconds.

Answer 2

${\bigstar}\large{\boxed{\sf{\pink{Given \: that}}}}$

• Acceleration = 4m/s¯¹
• Initial velocity = 0 m/s¯¹
• Time period = 10 seconds

${\bigstar}\large{\boxed{\sf{\pink{To \: find}}}}$

• Distance covered in 10 seconds after start.

${\bigstar}\large{\boxed{\sf{\pink{Analysis}}}}$

• Substitute the given value in the second equation of motion.
• The value we get after solving this is the distance.

${\bigstar}\large{\boxed{\sf{\pink{We \: know \: that}}}}$

• v = Final velocity
• a = Acceleration
• u = Initial velocity
• t = Time

${\bigstar}\large{\boxed{\sf{\pink{Solution}}}}$

Using the 2nd equation of motion,

Second equation = s = ut + 1/2at²

${\bigstar}\large{\boxed{\sf{\pink{Given \: that}}}}$

• Initial velocity = 0 m/s¯¹
• Acceleration = 4m/s¯¹
• Time = 10 seconds

$\large\purple{\texttt{Substituting the values}}$

s = 0 × 1/2 (4) (4)

s = 200 m

Therefore the car wil covered the distance of 200 metres after 10 seconds.

@Itzbeautyqueen23

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