a racing car has a uniform acceleration of 4 m/s at distance will it cover in 10 sec after the start
Answers
Answered by
15
it can be done by the formula
S=u*t+1/2*a*t*t ( third equation of motion)
u=0
t=10 sec
a= 4m/s
therefore,
S= 0*10+1/2*4*10*10
= 200m
ans: 200 m
S=u*t+1/2*a*t*t ( third equation of motion)
u=0
t=10 sec
a= 4m/s
therefore,
S= 0*10+1/2*4*10*10
= 200m
ans: 200 m
Answered by
1
This answer can be solved using the second equation of motion i.e
S=UT +1/2*AT^2 where s=distance
S= 0+2*100 u=initial velocity
S=200 m t=time
a=acceleration
Similar questions