A racing car has a uniform acceleration of 4 m/ seccond square . what distance will it cover in 10 sec after starts
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Hi.
Here is your answer---
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Given---
Acceleration(a) = 4 m/s²
Time(t) = 10 s
Initial Velocity(u) = 0
Using the Equations of the Laws of Motion,
S = ut + 1/2 × a × t²
= 0 × 10 + 1/2 × 4 × 10²
= 0 + 2 × 100
= 200 m.
Thus, the Distance Covered by the Car is 200 m.
_____________________
Hope it helps.
Have a nice day.
Here is your answer---
___________________
Given---
Acceleration(a) = 4 m/s²
Time(t) = 10 s
Initial Velocity(u) = 0
Using the Equations of the Laws of Motion,
S = ut + 1/2 × a × t²
= 0 × 10 + 1/2 × 4 × 10²
= 0 + 2 × 100
= 200 m.
Thus, the Distance Covered by the Car is 200 m.
_____________________
Hope it helps.
Have a nice day.
Answered by
0
Refer https://brainly.in/question/4391450
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