Question

A racing car has a uniform acceleration
of 4 ms 2. What distance it covers in 10 s
after the start?​

Answer 1

Answer:

200m

Explanation:

a=4m/s²

t=10s

u=0m/s

Hence s=ut + at²/2

s=0*10 + 4*(10)²/2

s=2*100

s=200m

IT COVERS 200M

Answer 2

Answer:

s=ut+1/2 at^2

s=ut+1/2 at^2u = 0

s=ut+1/2 at^2u = 0a=4

s=ut+1/2 at^2u = 0a=4t=10

s=ut+1/2 at^2u = 0a=4t=10s= 1/2 (4) (100)

s=ut+1/2 at^2u = 0a=4t=10s= 1/2 (4) (100)s= 200m

s=ut+1/2 at^2u = 0a=4t=10s= 1/2 (4) (100)s= 200mhope this helps.....