A racing car has a uniform acceleration of 4 ms square. What distance it covers in 10 s after start?
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7
Here's ur answer ..
As per the question..,
acc. (a) = 4m/s²
time (t) = 10s
initial velocity (u) = 0m/s
distance (s) = ?¿
By using eq. of motion..,
s = ut + ½ at²
s = 0(10) + ½ (4)(10)(10)
s = 0 + 2(100)
s = 200m
Distance travelled by the racing car in 10s is 200m.
Thanks !
As per the question..,
acc. (a) = 4m/s²
time (t) = 10s
initial velocity (u) = 0m/s
distance (s) = ?¿
By using eq. of motion..,
s = ut + ½ at²
s = 0(10) + ½ (4)(10)(10)
s = 0 + 2(100)
s = 200m
Distance travelled by the racing car in 10s is 200m.
Thanks !
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0
Refer https://brainly.in/question/4391450
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